Today I found that to add items to a list at runtime, you use the following code:
lstItemsOrdered.Items.Add
Jacqueline You Visual Basic
Wednesday, May 30, 2012
LoanPayment & ComboBoxes
Today I found out that information that is entered in a combobox is actually treated as a string as opposed to the textbox format, where the property of text from a textbox can be treated as a Textbox.
GetPercentAmount(Me.cboRate.Text, rate, validData)
Sub GetDollarAmount(ByVal txtUserData As TextBox, ByRef dollars As Decimal, _
ByRef isValid As Boolean)
Sub GetPercentAmount(ByVal cboUser As String, ByRef percent As Double, ByRef isValid _
As Boolean)
GetPercentAmount(Me.cboRate.Text, rate, validData)
Sub GetDollarAmount(ByVal txtUserData As TextBox, ByRef dollars As Decimal, _
ByRef isValid As Boolean)
Sub GetPercentAmount(ByVal cboUser As String, ByRef percent As Double, ByRef isValid _
As Boolean)
Wednesday, May 23, 2012
PerfectSquare
First, a random thought:
The word "perfect" is one of such wonderfully rounded curves that seem to convey the meaning of itself - perfection.
I was trying to pursue perfection in this application that I created, and found it marred by errors instead.
First, I awkwardly forgot what an Int() function does. It rounds a number up to the nearest integer.
Then I got my variables mixed up:
number was the user-entered number; numRt was the square root of that number
I originally wrote:
If Int(number) = numRt Then
Return True
End If
What happened, of course, is that only 1 returned a true statement (only the square root of 1 could possibly equal 1).
This below would return the correct answer.
If Int(numRt) = numRt Then
Return True
End If
This is my final code
Dim num As String = Val(Me.txtNumber.Text)
If PerfectSquare(num) = True Then
Me.lblAnswer.Text = num & " is a perfect square."
Else
Me.lblAnswer.Text = num & " is not a perfect square."
End If
End Sub
Function PerfectSquare(ByVal number As Double) As Boolean
Dim numRt As Double = Math.Sqrt(number)
If Int(numRt) = numRt Then
Return True
End If
End Function
Private Sub txtNumber_TextChanged(ByVal sender As Object, ByVal e As System.EventArgs) Handles txtNumber.TextChanged
Me.lblAnswer.Text = ""
End Sub
The word "perfect" is one of such wonderfully rounded curves that seem to convey the meaning of itself - perfection.
I was trying to pursue perfection in this application that I created, and found it marred by errors instead.
First, I awkwardly forgot what an Int() function does. It rounds a number up to the nearest integer.
Then I got my variables mixed up:
number was the user-entered number; numRt was the square root of that number
I originally wrote:
If Int(number) = numRt Then
Return True
End If
What happened, of course, is that only 1 returned a true statement (only the square root of 1 could possibly equal 1).
This below would return the correct answer.
If Int(numRt) = numRt Then
Return True
End If
This is my final code
Dim num As String = Val(Me.txtNumber.Text)
If PerfectSquare(num) = True Then
Me.lblAnswer.Text = num & " is a perfect square."
Else
Me.lblAnswer.Text = num & " is not a perfect square."
End If
End Sub
Function PerfectSquare(ByVal number As Double) As Boolean
Dim numRt As Double = Math.Sqrt(number)
If Int(numRt) = numRt Then
Return True
End If
End Function
Private Sub txtNumber_TextChanged(ByVal sender As Object, ByVal e As System.EventArgs) Handles txtNumber.TextChanged
Me.lblAnswer.Text = ""
End Sub
Thursday, May 17, 2012
MetricConversion
This application involved entering a number and being able to convert between metric/customary units for various lengths.
I made a few errors while typing this program
The first one was that I treated a function like a procedure and typed:
finalNumber=(initialNum*2.54)
Return finalNumber
I changed this to:
Return (initialNum * 2.54)
after Ms. Stark pointed out my error.
The second mistake I made was I predefined finalNumber as being equal to zero:
Dim finalNumber As Double
The third mistake I made was that I forgot to type in the tags. Oops.
I made a few errors while typing this program
The first one was that I treated a function like a procedure and typed:
finalNumber=(initialNum*2.54)
Return finalNumber
I changed this to:
Return (initialNum * 2.54)
after Ms. Stark pointed out my error.
The second mistake I made was I predefined finalNumber as being equal to zero:
Dim finalNumber As Double
The third mistake I made was that I forgot to type in the tags. Oops.
Thursday, May 10, 2012
LetterGrade
This program returns a letter grade when a test score is entered.
The program that my modified version is based on uses A=90 or above, B=80 and above, etc. I changed it to display A+, A-, etc. by adding in additional ElseIf statements. I also had to change the Function's type from Char to String.
Function LetterGrade(ByVal score As Double) As String
If score >= 97 Then
Return "A+"
ElseIf score >= 93 Then
Return "A"
ElseIf score >= 90 Then
Return "A-"
The program that my modified version is based on uses A=90 or above, B=80 and above, etc. I changed it to display A+, A-, etc. by adding in additional ElseIf statements. I also had to change the Function's type from Char to String.
Function LetterGrade(ByVal score As Double) As String
If score >= 97 Then
Return "A+"
ElseIf score >= 93 Then
Return "A"
ElseIf score >= 90 Then
Return "A-"
Wednesday, May 9, 2012
Add Coins
I made a very simple mishap here. I used two equal signs and wrote total = (quart * 0.25) + (dime * 0.1) = (nick * 0.05) + (penny * 0.01), instead of total = (quart * 0.25) + (dime * 0.1) + (nick * 0.05) + (penny * 0.01) with only one equal sign.
CD DVD Tips
This was the code I wrote originally:
Private Sub btnTip_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btnTip.Click
Call Message(Me.lblTip)
End Sub
'After button has been clicked, a random number will be chosen that represents one of the three tips
'post: the tip will show up in the label
Sub Message(ByRef lblMessage As Label)
Randomize()
Dim tipNumber As Integer
tipNumber = Int(3 * Rnd()) + 1
Select Case tipNumber
Case 1
lblMessage.Text = "Handle CD/DVDS by the center hole or by the edges."
Case 2
lblMessage.Text = "Keep CD/DVDs away from extreme temperatures and moisture."
Case 3
lblMessage.Text = "Store discs in a jewel case or sleeve to prevent scratches."
End Select
This is the updated version with parameters based on TestRndIntFunction
Dim lowNum As Integer = 1
Dim highNum As Integer = 3
Dim chosenNum As Integer
Call RndInt(lowNum, highNum, chosenNum)
If chosenNum = 1 Then
Me.lblTip.Text = "Handle CD/DVDS by the center hole or by the edges."
ElseIf chosenNum = 2 Then
Me.lblTip.Text = "Keep CD/DVDs away from extreme temperatures and moisture."
Else
Me.lblTip.Text = "Store discs in a jewel case or sleeve to prevent scratches."
End If
End Sub
'After button has been clicked, a random number will be chosen that represents one of the three tips
'post: the tip will show up in the label
Sub RndInt(ByVal firstNum As Integer, ByVal secondNum As Integer, ByRef thirdNum As Integer)
Randomize()
thirdNum = ((secondNum - firstNum + 1) * Rnd()) + firstNum
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